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JEE Normalized Percentile Method cl+0.5 fi /N x 100 Good or Bad ?

Normalization Procedure for Class XII Board Marks

In view of large scale variations in the examination system in country, the JEE Interface Group (JIG) decided  that for this year  (2013), 50% of Boards  marks  be  normalized  by equating percentile amongst different boards/examining  bodies and anchoring them to All  India  JEE-Main  percentiles,  and  50%  be  normalized  by  equating  each Board’s/examining   Body’s  percentile  with  JEE(Main)  percentile   marks  of  respective Boards /examining bodies.

Accordingly, the detailed procedure for normalization of Board marks will be as follows:- i.      Note down the aggregate marks (A0) obtained by each student in JEE- Main.

ii.      Compute the percentile (P) of each student on the basis of aggregate marks in his/her own

board (B0) computed from the list of five subjects specified (each marked out of 100). The percentile is to be computed among all students of the board whose subject combinations meet the eligibility criteria of JEE-Main.

iii.      Determine the JEE- Main aggregate marks corresponding to percentile (P) at the All- India level. Regard this as B1.

iv.      Also, determine the JEE- Main aggregate marks corresponding to percentile (P) among the

set of aggregate scores obtained in the JEE- Main by the students of that board. Regard this as B2.

The normalized board score of the candidate will be computed as: Bfinal = 0.5 * (B1 + B2)

For the purpose of admission to CFTIs where it has been decided to use the JEE Mains

performance  and the Normalized Board performance  in the 60:40 ratio, the composite score for drawing the merit list will be computed as:

C = 0.6 *  AO + 0.4 * Bfinal,

Five subjects to be used for normalization:-

1.   Physics

2.   Mathematics

3.   Any one of the subjects Chemistry, Biology, Biotechnology and Computer Science

4.   One language

5.   Any subject other than the above four subjects.

In respect of 3, 4 and 5, the best mark in a given category will be chosen. For any query please write to  jeemainnormalisation2013@gmail.com

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After the announcement of Government of India about Common Entrance Test from 2013 for all IIT, NIT and IIIT colleges there is only one question from students what is  cl+0.5 fi /N x 100 and who are going to benefit with Normalized Percentile Method Private Colleges or Government colleges or which state is going to grab more seats:

Lets see what is this Normalized Percentile Method:

Count of all scores less than score of interest +0.5  frequency of the score of interest  /Number of Examines in the sample x 100 which is prepared by the Ramasami Committee and experts from ISI Kolkata.

This Common Entrance will have two papers Main Paper of 3 hours and Advance Paper of 3 hours. The rank will be based on the weight-ages of their respective board (CBSC or State Board) marks – 40 percent, main test 30 percent and advance test 30 per cent. Tie-breaks will be handled in the order of board percentile rank, main test marks, advance test marks, and marks in the subject with the lowest, second lowest and third lowest, average marks of the advance test.

And coming to the interesting topic who are going to benefit from this Method is it Andhra Pradesh ?

As earlier if Andhra Pradesh students scores more marks in intermediate examination conducted by Board of Intermediate Education (BIE) then it will create a big problem for the students who will score less then three to five  percent less then toppers in BIE.

For example as per the statistics the students who got 920 to 940 expected to get more IIT seat then 960 to 980 marks scored in BIE. From now corporate colleges in Andhra Pradesh should concentrate more on Subject not on marks scored in BIE.

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